# Creating Number Patterns In Java

Creating number or symbol patterns is used to check command of a programmer or a student on for loop. In short its done just for practicing for loop.

Here are some common number patterns :

Pattern 1.
To Print this pattern use the following code:

```public class numPtr {
public static void main( String arg[]){
for(int i=1;i<=5;i++){

for(int j=1;j<=i;j++){
System.out.print(j);
}
System.out.println();
}
}
}
```

Pattern 2.
To Print this pattern use the following code:

```public class numPtr {
public static void main( String arg[]){
for(int i=1;i<=5;i++){
for(int j=5;j>=i;j--){
System.out.print(j);
}
System.out.println();
}
}
}
```

Pattern 3.
To Print this pattern use the following code:
```public class numPtr {
public static void main( String arg[]){
for(int i=1,r=5;i<=5;i++,r--){
for(int j=1;j<=r;j++){
System.out.print(j);
}
System.out.println();        }
}
}
```

Pattern 4.

To Print this pattern use the following code:
```public class numPtr {
public static void main( String arg[]){
int ck=0,c=2;
while(c>0){
if(ck==0){
for(int i=1;i<=5;i++){
for(int j=1;j<=i;j++){
System.out.print(j);
}
System.out.println();         }
ck++;
} else{
for(int i=1,r=5-1;i<=5-1;i++,r--){
for(int j=1;j<=r;j++){
System.out.print(j);            }
System.out.println();
}
}
c--;
}

}
}

```
Pattern 5.

To Print this pattern use the following code:
```public class numPtr {
public static void main( String arg[]){
int ck=0,c=2;
while(c>0){
if(ck==0){
for(int i=1,r=5;i<=5;i++,r--){
for(int j=1;j<=r;j++){
System.out.print(j);
}
System.out.println();        }
ck++;
} else{
for(int i=2;i<=5;i++){
for(int j=1;j<=i;j++){
System.out.print(j);            }
System.out.println();
}
}
c--;
}

}
}
```
Author Note: All the above examples gives output till 5, you can change it accordingly by changing the conditions.

PRINT THE SUM OF THE SERIES:
1-2+3-4+5-6+7..........n

hello sir i want a code to print 3rd math table.........the result must be odd numbers in the table that means only odd numbered result have to print,should be in line by line format.........thank you.

class Pattern3 {
public static void main(String[] args){
int i,j,k=1;
for(i=5;i>=1;i--){
for(j=k;j<=5;j++){
System.out.print(j);
}
k++;
System.out.println();
}
}
}

SOOOS
OSOSO
OOSOO
OSOSO
SOOOS
can any one help me out this pattern.........

i want to learn java...these are my basic questions...
Q1 : Check whether number is prime or not if prime then print all prime number upto 50 and generate sum .
Q 2 : Write a program to find the product of the sums of all odd & even digits in a given number ?
Q 3 : Write a program to find the number & sum of all Integers 100>no.>200 that is divisible by 7 ?
Q 4 : Write a program in java to find the largest of 3 numbers by using conditional operator ?
Q 5: Write a program in java to sort the elements of an array in ascending order by using bubble sort ?
Q 6 : Write a program in java to implement matrix multiplication ?
Q 7 : Check number is even or not if even then print list in reverse order [range 1 -60]
Q 8 : Write a program in java to display the first 10 numberof Fibonacci series and find factorial of the last number of the produced Fibonacci series.
Q 9 : Write a simple program to implement constructor ?

what is the coding for this patterns

1
2 3
4 5 6
7 8 9 10
11 12 13 14 15

&

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1

can you help me for this pattern

1
0 0
1 1
0 0
1

public class Third {

public static void main(String[] args) {

int y=1;
int m=1;
for(int i=1;i<=5;i++){

if(i==1 || i==5){
System.out.print(m);
}
else{
if(i%2==0){
y=0;
}
else{
y=1;
}
for(int k=1;k<=2;k++){
System.out.print(y+" ");

}
}

System.out.println();
}
}

}

public class Third {

public static void main(String[] args) {

int j=1;
for(int i=1;i<=5;i++){
for(int k=1; k<=i; k++){
System.out.print(j+" ");
j++;
}
System.out.println();
}

}

}

Thanks Anand prakas yadav for solving everyone's problem. We really appreciate this!

public class Third {

public static void main(String[] args) {

for(int i=1;i<=9;i++){
int u=i-1;
for(int j=1;j<=i;j++){
System.out.print(j);
}
for(int k=1;k<=i-1;k++){
System.out.print(u);
u--;
}
System.out.println();
}

}

output is-------

1
121
12321
1234321
123454321
12345654321
1234567654321
123456787654321
12345678987654321

sir we solve the following pattern in how many ways :
------1
-----121
---12321
-1234321
---12321
-----121
-------1

Reply soon SiR. thank U :)

package abc;

public class Six {

public static void main(String[] args) {
// TODO Auto-generated method stub
int v=4;
int r=2;
for(int i=1;i<=4;i++){
for(int l=1;l<=v;l++){

System.out.print("-");

}
int u=i-1;
for(int j=1;j<=i;j++){
System.out.print(j);
}
for(int k=1;k<=i-1;k++){
System.out.print(u);
u--;
}

v=v-1;
System.out.println();
}
for(int t=1;t<=3;t++){
for(int y=1;y<=r;y++){
System.out.print("-");

}

int u=3-t;
for(int j=1;j<=4-t;j++){
System.out.print(j);
}
for(int k=1;k<=3-t;k++){
System.out.print(u);
u--;
}

r=r+1;
System.out.println();

}

}

}

you can solve this pattern in many ways like as using while or other methods.Because you can solve any problem in many ways.

thank U sir . u got programming powers :D

can u pls help me get coding for my programs

for this pattern...
0
0 2
0 2 4
0 2 4 6
0 2 4 6 8

1 5 10 10 5 1
1 4 6 4 1
1 3 3 1
1 2 1
1 1
1

can you solve this ??

11111
22221
33321
44321
54321

public class Example {

public static void main(String[] args) {
// TODO Auto-generated method stub

for(int i=1; i<=5;i++){
int s=i;
for(int g=1;g<=6-i;g++){

System.out.print(i);

}

for(int h=1;h<=i-1;h++){

System.out.print(s-1);
s--;
}
System.out.println();
}

}

}

public class Example {

public static void main(String[] args) {
// TODO Auto-generated method stub

int e=0;

for(int i=1; i<=5;i++){

for(int g=1;g<=i;g++){

System.out.print(e+" ");
e+=2;

}

e=0;
System.out.println();
}

}

}

*
* *
* * *
* * * *
* * * * * *
* * * *
* * *
* *
*

this 1 sir whats the code

1
3 5
7 9 11
13 15 17 19
send me program for this pattern

send me program sir.......

sir plzzzzzz help

1
1 2 1`
1 2 3 2 1
1 2 3 4 3 2 1

public class Example4 {

public static void main(String[] args) {
// TODO Auto-generated method stub

int g=1;
for(int i=1; i<=4;i++){
for(int j=1; j<=i;j++){

System.out.print(g+" ");

g+=2;
}
System.out.println();
}

}

}

public class Pattern {

public static void main(String[] args) {
// TODO Auto-generated method stub

for(int i=1;i<=5;i++){
for(int j=1;j<=i;j++){
System.out.print("*");
if(j==5){
System.out.print("*");
}
}
System.out.println();
}
for(int h=1;h<=4;h++){
for(int t=4;t>=h;t--){
System.out.print("*");
}
System.out.println();
}

}

}

public class Man {

public static void main(String[] args) {

for(int i=1;i<=4;i++){
int u=i-1;
for(int j=1;j<=i;j++){
System.out.print(j+" ");
}
for(int k=1;k<=i-1;k++){
System.out.print(u+" ");
u--;
}
System.out.println();
}

}

}

hello can you help me printing this
***
**
*

sir plz help me for this pattern
15 14 13 12 11
10 9 8 7
6 5 4
3 2
1

class Pattern
{
public static void main(String args[])
{
int n=3;
for(int i=0;i<n;i++)
{
for(int j=i;j<n;j++)
{
System.out.print("*");
}
System.out.println();
}
}
}

finally i done.
------------------------------------------------------------------------------------
class NumPattern
{
public static void main(String args[])
{
int ln=5;
int x=15;
for(int i=1;i<=5;i++)
{
for(int j=ln;j>=i;j--)
{
System.out.print(x+" ");
x--;
}
System.out.println();
}
}
}

Sir please give me a java code for the pattern
..........1
.......1 2 1
....1 2 3 2 1

Please check comment <30/> above, same program solved there!

This comment has been removed by the author.

Hello Akshay!
Please check comment no. <39/> or <96/> above.... same question solved there!

Looks like you didn't check the above comments I mentioned :)
Ok, so you can grab your code with correct spacing you want below:

class Main1 {
public static void main(String Args[]) {
int max = 4;    //max no. in series
//Upper Triangle
for(int i=1;i<=max;i++){
for(int s=0;s<max-i;s++){
System.out.print(" ");  //Spacing
}
for(int j=1;j<=i;j++){
System.out.print(j);    //ascending print
}
for(int k=i-1;k>=1;k--){
System.out.print(k);    //descending print
}
System.out.println();       //new line
}
//Lower Triangle
for(int i=1;i<=max-1;i++){
for(int s=max-i;s<max;s++){
System.out.print(" ");  //Spacing
}
for(int j=1;j<=max-i;j++){
System.out.print(j);    //ascending print
}
for(int k=max-i-1;k>=1;k--){
System.out.print(k);    //descending print
}
System.out.println();       //new line
}
}   //end of main
}

Hope that's what you looking for!

Can I get the code for these pattern s
123454321
1234 4321
123 321
12 21
1 1

And
1
121
12321
1234321

Hello!
Kindly scroll to top and check comment no. 11 and 41 for both of your questions solution respectively....

1 6 10 13 15
2 7 11 14
3 8 12
4 9
5

class Main1 {
public static void main(String Args[]) {
int rows=5 , i , j , k , print;
for( i=1; i<=rows; i++ ){
for( j=rows-i,k=0,print=i; j>=0; j--,k++ ){
System.out.print(print+" ");
print+=rows-k;
}
System.out.println();
}
}
}

Anonymous

pls sir print the this name=sagar
in the start pattern

Anonymous

pls sir print the this name=sagar
in the start pattern

Sir can we right the last for loop like this?
for (int j=0; j <i; j++, cout++)

Yes Prajwal we can write like this as well

-------*
------*1*
----*121*
---*12321*
--***********

public class pattern8
{
public static void main(String args[])
{
int i,j,k,c=1;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
System.out.print(j);
System.out.print(" ");
for(k=c;k>=1;k--)
System.out.print(k);
System.out.println();
c++;
}
}
}

Regs

public class pattern8
{
public static void main(String args[])
{
int i,j,k,c=1;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
System.out.print(j);
System.out.print(" ");
for(k=c;k>=1;k--)
System.out.print(k);
System.out.println();
c++;
}
}
}

SIR CAN YOU GIVE ME CODE FOR THE FOLLOWING CODE:
A
AB
ABC
ABCD
ABCDE

Sir,
I need help in this program :

123456789
2345678
34567
456
5
456
34567
2345678
123456789

hello world

Better program for pattern 4 without using another r variable.
package patterns;

public class Bow_number_pattern {
public static void main(String[] args) {
/* 1
* 1 2
* 1 2 3
* 1 2 3 4
* 1 2 3 4 5
* 1 2 3 4
* 1 2 3
* 1 2
* 1
*/
int i,j;
int increase_loop_count=0,decrease_loop_count=1;
while(decrease_loop_count>=1)
{
if(increase_loop_count==0)
{
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
System.out.print(j+" ");
System.out.println();
}
increase_loop_count++;
}
else
{
for(i=1;i<=5-1;i++)
{
for(j=1;j<=5-i;j++)
System.out.print(j+" ");
System.out.println();
}
decrease_loop_count--;
}

}

}

}

write code for
2
4 6
8

hello sir, could u plz help me out in getting this pattern?
1
01
101
0101
10101

what will be the code for this pattern?
1A 3B 5A
1B 3A 5B
2A 4B 6A
2B 4A 6B

class Pattern
{
public static void main(String args[])
{
int n=5;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
System.out.print(j);
}
if(i==n)
{
System.out.print("");
}
else
System.out.print(" ");
for(int k=i;k>=1;k--)
{
System.out.print(k);
}
System.out.println();
}
}
}

A B C D E D C B A
A B C D D C B A
A B C C B A
A B B A
A A
pls help me out find the code fr dis program

pls sir can u help me solve dis program plzzzzz!!!!
1. 123456789
2345678
34567
456
5
456
34567
2345678
123456789

Sir.. Plz help me to solve this..

___2_________4____
_2_4_2_____3_4_3_
2_4_6_4_2_3_4_3_2
_1_3_1_____3_4_3__
___1_________4_____

Plz.. Reply as soon as possible.. (__ its space.. Hope u can understand)

SIR
Could you tell me the code for this following pattern
1
333
55555
7777777
55555
333
1

Pl help me with this Patten
------------1
---------1 2
------1 2 3
---1 2 3 4
1 2 3 4 5
- spaces can be anything but alignment should be maintained as shown pl help me

This comment has been removed by the author.

class PatternShape
{
public static void main(String[] ar)
{
int n=5;
for(int i=1;i<=5;i++)
{
for(int s=1;s<=n-i;s++)
{
System.out.print("-");
}
for(int j=1;j<=i;j++)
{
System.out.print(j);
}
System.out.println();
}
}
}

class PatternsDemo
{
public static void main(String[] ar)
{
int n=7;
for(int i=1;i<=n;i+=2)
{
System.out.println("");
for(int j=1;j<=i;j++)
{
System.out.print(i);
}
}
for(int i=n-2;i>0;i-=2)
{
System.out.println("");
for(int j=i;j>0;j--)
{
System.out.print(i);
}
}
}
}

class PatternDemo
{
public static void main(String[] ar)
{
int n=5;
for(int i=0;i<5;i++)
{
System.out.println("");
for(int j=i+1;j<=9-i;j++)
{
System.out.print(j);
}
}
for(int i=n-1;i>0;i--)
{
System.out.println("");
for(int j=i;j<=9-(i-1);j++)
{
System.out.print(j);
}
}
}
}

class PatternDemo
{
public static void main(String[] ar)
{
int n=5;
for(int i=0;i<5;i++)
{
System.out.println("");
for(int j=i+1;j<=9-i;j++)
{
System.out.print(j);
}
}
for(int i=n-1;i>0;i--)
{
System.out.println("");
for(int j=i;j<=9-(i-1);j++)
{
System.out.print(j);
}
}
}
}

class CodeDemo
{
public static void main(String[] ar)
{
int n=5;
for(int i=1;i<=n;i++)
{
System.out.println("");
for(int j=1;j<=i;j++)
{
if(i==1)
{
System.out.print("1");
}
else
{
if(i%2==0)
{
if(j%2==0)
System.out.print("1");
else
System.out.print("0");
}
else
{
if(j%2==0)
System.out.print("0");
else
System.out.print("1");
}
}
}
}
}
}

pls tell me the code
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5

pls sir help me to get the code for
1
1 1
1 1 1
1 1 1 1
1 1 1 1 1

prg to print prime numbers from 1 to 100

class Jamer
{
public static void main(String...s)
{
for(int i=1;i<=5;i++)
{
for(int j=1;j<=i;j++)
{
System.out.print(j);
}
System.out.print(" ");
for(int k=i;k>=1;k--)
{
System.out.print(k);
}
System.out.print("\n");
}
}
}

{
public static void main(String[] ar)
{
int i,j;
for(i=1;i<=100;i++)
{
int count=0;
for(j=1;j<=i;j++)
{
if(i%j==0)
count++;
}
if(count==2)
{
System.out.print(i+"\t");
}
}
}
}

123456789
2345678
34567
456
5
456
34567
2345678
123456789

Hi sir,
How do you print the following pattern:

1 1 1 1 1 1 1 1 1
1 2 2 2 2 2 2 2 1
1 2 3 3 3 3 3 2 1
1 2 3 4 4 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 4 4 3 2 1
1 2 3 3 3 3 3 2 1
1 2 2 2 2 2 2 2 1
1 1 1 1 1 1 1 1 1

Please tell me the java program for the pattern

1
121
12321
1234321
12321
121
1

Greetings sir....cud u plz solve these patterns...
1) 1 2 3 4 5
6 7 8 9
10 11 12
13 14
15

2) 15 14 13 12 11
10 9 8 7
6 5 4
3 2
1

3) 1 3 5 7 9
3 5 7 9 1
5 7 9 1 3
7 9 1 3 5
9 1 3 5 7

ASAP will be deeply appreciated...thnx n advance.....

Hi,
1 6
2 7
3 8
4 9
5 10

1
2 2 2
3 3 3 3 3
4 4 4 4 4 4 4
5 5 5 5 5 5 5 5 5

5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

PLEASE TELL ME HOW TO PRINT
3 33 333 3333 33333
3 33 333 3333 33333
3 33 333 3333 33333
3 33 333 3333 33333
3 33 333 3333 33333

1
1 A
1 A 1
1 A 1 B
1 A 1 B 1

import java.io.*;
class Pat
public void main() throws IOException
{ System.out.println("Input a string:");
System.out.println();
int len=str.length();
for(int i=0; i<len; i++)
{ char ch=str.charAt(i);
for(int j=1; j<i+2;j++)
{
System.out.print(ch);
}
System.out.println();
}
}
}

what is code for
11111
12221
13331
14441
11111

sir plz give me the code of this pattern

J
J A
J A V
J A V A
J A V A 2
J A V A 2 J
J A V A 2 J E
J A V A 2 J E E
J A V A 2 J E E 3

how to print when n is given =2
112
322

please provide code for following pattern
*
**
***
****
*****

sorry , following is the pattern i actually wanted to know:
----*
---**
--***
-****
*****

sir it is not pattern program but can you pls solve these 3 programs

1) to print the roman equivalent of the number which is entered(without using the method directly)
2) to enter a word and print a character only once if it is repeated in the word for ex. if i enter aabbccdd then the output should be abcd.
3) to enter an integer and give the result as the sum of its digits raise to the power of there position.
for ex. if i enter 491 then the output should be 4 to the power 1 + 9 to the power 2 + 1 to the power 3.

pls help sir

1
2 3
4 5 6
7 8 9 10
11 12 13 14 15

how to print
1
23
456
78910
1112131415

I want a java program which should display the following output

H
HE
HEL
HELL
HELLO
HELL
HEL
HE
H

****1
***2*
**3**
*4***
5****
*6***
**7**
***8*
****9
with stars!
can i get the correct code for this pattern

can u help me in printing the following pattern upto a given limit...
for example if iam giving the limit as 12 my output should be
0
0 2
2 4 6
6 8 10 12

can u help me to print the pattern
0
0 2
2 4 6
6 8 10 12

1 2 3 4 5
2 4
3 3
4 2
5 4 3 2 1

Help me in doing this pattern using loops only:
* * * * * *
*
*
*
*
* * * * *

class Main1 {
public static void main(String[] args){
int n = 6;
for(int i=0;i<n;i++){
if(i==0 || i==n-1){
for(int j=0;j<n;j++){
System.out.print("*");
}
} else{
System.out.print("*");
}
System.out.println();
}
}
}

123456787654321
1234567_7654321
123456___654321
12345_____54321
1234_______4321
123_________321
12___________21
1_____________1

123454321
1234_4321
123___321
12_____21
1_______1

Sample output for 3 rows
1 3 5
* 2 *
1 3 5

(Ques-1)

A
AB
ABC
ABCD
ABCDE

(Ques - 2)

H
HE
HEL
HELL
HELLO
HELL
HEL
HE
H

Problem Statement: x pattern using 1 and o s center

Generate the following pattern for an input say 1110111 where equal number of 1's can be prefixed and suffixed where 0 must be at the middle position and the total number of digits must be odd.
1 1
1 1
1 1
0
1 1
1 1
1 1

Dos and Donts

Minimum no. of digits should be 3, say 101.
Maximum no. of digits should be 19.
Input should be read as long data type.
(Don't read the input as String type)

S
S U
S U S
S U S H
S U S H I
SIR, pls help me to solve this program

Hello Sir,

0 1 1 1 1
1 2 2 2 2
3 4 4 4 4
5 6 6 6 6
7 8 8 8 8

Check comment no. 27 and 64 for source code!

# # # # # # #
#
#
#
#
#
# # # # # # #
Any one can help me to do this ? :)

can you help me
1
12
123
123
12
1

1
2 6
3 7 10
4 8 11 13
5 9 12 14 15
write a program to print above triangle

int rows=5 , i , j , k , print;
for( i=1; i<=rows; i++ )
{
for( j=i,k=1,print=i; j>0; j--,k++ )
{
System.out.print(print+" ");
print+=rows-k;
}
System.out.println();
}

This comment has been removed by the author.

what will be the code for
@ # #
@ @ #
@ @ @

what will be the code for
@ # #
@ @ #
@ @ @

a
ab
abc
abcd
and so on upto specified number of letters. How do you do it?

just a correction..
i would like to have the solution program only with two variables(eg..i and j).
thank you

sir i have another also:-
1 1
12 21
123 321
1234 4321
1234554321

Check comment no. 1 and 11 for solution of this pattern.

12345
1234
123
12
1

1
12
123
1234
12345

can you give java source code for the following as fast as possible(very urgent):-
(i)
1
121
12321
1234321
12321
121
1

pls help me with this pattern prog
1
13
135
1357
13579

how to print the sum of series..?
1. s=a+a^2/2!+a^3/3!+................a^n/n!
2. s=x/3+x/8+x/15......n

1
3 2
6 5 4
10 9 8 7

4
2 5 7
1 3 6 8 9

This comment has been removed by the author.

public class Patterns1{
public void main(int n){
for(int i=1;i<=(2*n-1);i++){
if(i<=n)
print(i);
else
print(2*n-i);
System.out.println();
}
}
public void print(int x){
for(int i=1;i<=(2*x-1);i++)
if(i<=x)
System.out.print(i+" ");
else
System.out.print((2*x-i)+" ");
}
}

- - 4
- 2 5 7
1 3 6 8 9

could u send the code for below pattern

*
* *
* *
* *
*

1
1 2 1
1 2 4 5 1
1 3 5 9 14 15 1

need this pattern..

Thanks

1
2 3 4
5 6 7 8 9
10 11 12 13 14 15 16

sir, please give the code for this

Dear sir
how to print W format out put
* *
* * *
* * * *
* *

I want code for following pattern
for n=4
1111
1001
1001
1111

n=5

11111
10001
10101
10001
11111

*
* *
* *
* *

*
* *
* *
* *

1***
12**
123*

public static void main(String[] args) {
// TODO Auto-generated method stub
int n = 5;

for (int i = 1; i <= n; i++) {
for (int j = 1; j <= i; j++) {
System.out.print(j);
}
System.out.print(" ");
for (int j = i; j >= 1; j--) {
System.out.print(j);
}
System.out.print("\n");
}
}

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class pattern
{
public static void main(String args[])throws IOException
{
int n=5;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
System.out.print(j);
}
for(int k=i;k>=1;k--)
{
System.out.print(k);
}
System.out.println();
}

}
}

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class pattern
{
public static void main(String args[])throws IOException
{
int n=5;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
System.out.print(j);
}
for(int k=i;k>=1;k--)
{
System.out.print(k);
}
System.out.println();
}

}
}

sir I want to know how do u tackle any pattern programs.I want to learn n understand ur logical thinking process ability. plz plz do rply.

Can you please solve this by today? Its for my computer exam tomorrow...thanks in advance
123454321
1234 4321
123 321
12 21
1 1

Scroll up and search for comment <11/> or just search your pattern in 'search box' you will find my previous solution for the same pattern.
Best of luck for your exam :)

Try to create 5 to 10 patterns manually with/without taking any hint you will get the logic what's same in every pattern.....
I suggest you to practice regularly for 3-4 days and try to understand how the numbers (to be printed) are generated and how next value is related to previous values!

public class pyanum
{
public static void main ( String [] args )
{
int i,j;
for(i=1;i<=5;i++)
{
for(j=i;j<=5;j++)
{
System.out.print(j);
}
System.out.println();
}
}
}

i want this pattern code plz help me sir
111112
311112
311114
511114
511116
and so on

Sir i want an output as follows:

Enter a string in between A to Z (only odd characters like A or C or E )

ABCDEDCBA
ABCD DCBA
ABC CBA
AB BA
A A

Sir i want an output as follows:

Enter a string in between A to Z (only odd characters like A or C or E )

ABCDEDCBA
ABCD DCBA
ABC CBA
AB BA
A A

public static void main(String args[])
{
int i,j,k;
for(i=4;i>=1;i--)
{
for(j=1;j<4;j++)
{
if(j<=i)
System.out.print(j);
else
System.out.print(" ");
}
for(j=4;j>=1;j--)
{
if(j<=i)
System.out.print(j);
else
System.out.print(" ");
}
System.out.println();
}
}
}

HI gil,
here program for above pattern

public static void main(String args[])
{
int i,j,k;
for(i=4;i>=1;i--)
{
for(j=1;j<4;j++)
{
if(j<=i)
System.out.print(j);
else
System.out.print(" ");
}
for(j=4;j>=1;j--)
{
if(j<=i)
System.out.print(j);
else
System.out.print(" ");
}
System.out.println();
}
}
}

OUTPUT SHOULD BE DISPLAYED AS FOLLOWS:
> Enter an odd character in between A and Z
> User will enter "E"nce the user enter E. the output displayed should be as followed

ABCDEDCBA
ABCD DCBA
ABC CBA
AB BA
A A

11
21 22
31 32 33
41 42 43 44
51 52 53 54 55

11
21 22
31 32 33
41 42 43 44
51 52 53 54 55

11
21 22
31 32 33
41 42 43 44
51 52 53 54 55

11
21 22
31 32 33
41 42 43 44
51 52 53 54 55

*
***
****
***
*

This comment has been removed by the author.

1
2 4
3 5 7
6 8 10 12

1
2 1
3 2 1
4 3 2 1

how to print this pattern
12345
2345
345
45
5

program for this pattern
12345
2345
345
45
5

1 2 3 4 5 6
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6

1
2 3
3 4 5
4 5 6 7
5 6 7 8 9
give me code for this

Check This Code

public class pattern
{

public static void main(String []args)
{

int i, j;

for(i=1;i<=5;i++)

{

for(j=i;j>=1;j--)

{

System.out.print(j%2);

}

System.out.println();

}

}

}

Write a java program that asks user a character ch and a integer n and print a S pattern using n lines
output:
ch=@
n=6
@@@@@@
@
@@@@@@
@
@@@@@@

///0///
//010//
/01210/
//010//
///0///
Note : / represents space.

1
00
11 1
0000
…..

Hello, i want a java code for the below pattern
1
2 6
3 7 10
4 8 11 13
5 9 12 14

Sir please can you help me with the code for
1
1+2=3
1+2+3=6
Till
1+2+3+4+5+6+7+8+9+10=55

This comment has been removed by the author.

import java.util.*;
public class pattern
{
public static void main(String args[])
{
int n,i,j;
Scanner sc=new Scanner(System.in);
System.out.println("Enter the size of the pattern");
n=sc.nextInt();
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
if(i%2==0)
System.out.print("0");
else
System.out.print("1");
}
System.out.println();
}
}
}

check this code for
1
00
111
0000

Check this code Divya.

public class pattern7
{
public static void main(String args[])
{
int i,j;
for(i=6;i>=1;i--)
{
for(j=1;j<=i;j++)
{
System.out.print(j+" ");
}
System.out.println();
}
for(i=2;i<=6;i++)
{
for(j=1;j<=i;j++)
{
System.out.print(j+" ");
}
System.out.println();
}
}
}

Hello Vasavi !!!!
Try this code

public class pattern9
{
public static void main(String args[])
{
int i,j;
for(i=0;i<=4;i++)
{
for(j=i;j>=1;j--)
{
System.out.print(j);
}
System.out.println();
}
}
}

Class abc {
Void display{
Int p =3 ;
For(int x=0; x<=2;x++){
For(int y=1;y<=p;y++){
System.out.print(" ");}
For(int z=0;z<=x;z++){
System.out.print(z);}
For(int i =2;i<=3-x;i--){
System.out.print(x-1);}
p=p-1;
System.out.println(" ");}
Int s= 2;
For(int n=1;n<=0;n--){
For(int m=1;m<=s;m++){
System.out.print(" ");}
For( int o =0;o<=n;o++){
System.out.print(o);}
For(int w = 2;w>=n;w--){
System.out.print(n-1);}
S++;
System.out.println(" ");}
}
}

Wrong

public class pattern11 {
public static void main(String args[])
{
for(int i=1; i<=5; i++)
{
for(int j=1; j<=i; j++)
{
System.out.print(j);
}
System.out.print(" ");
for(int k=i; k>=1; k--)
{
System.out.print(k);
}
System.out.println();
}

5
545
54345
5432345
543212345

Sir ? How to code this

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1

Sir ? How to code this

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1

Write a method called printNumbers that accepts a maximum number as a parameter and prints each number from 1 up to that maximum, inclusive, boxed by square brackets. For example, consider the following calls:

printNumbers(15);
printNumbers(5);
These calls should produce the following output:

[1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] [13] [14] [15]
[1] [2] [3] [4] [5]

123454321
1234 4321
123 321
12 12
1 1

How to do this pattern? Please rply as soon as possible:
1234321
123 321
12 21
1 1
12 21
123 321
1234321

Where are these pattern problems used when tackling real life programming situations, like while developing certain kind of application?

Can u help with me this???

123456789
--12345678
----1234567
------123456
--------12345
----------1234
------------123
--------------12

This comment has been removed by the author.

Hello! ma-wabeauty, here's the code you want:

public class Pattern {
public static void main( String args[]){
for(int i=1 ; i<=8 ; i++){

for(int k=9-i ; k<8 ; k++){
System.out.print(" ");
}

for(int j=1 ; j<=10-i ; j++){
System.out.print(j);
}

System.out.println();
}

}
}

i have not understood

hi
if u could explain me use of int test,j,i in the prg

write a program to generate afollowing pattern :
\$
???
<<<<<
<<<<<<<
#########

Under recursive structure, a sum of a number X is equal to X+(X-1)+(X-2)+...+1.
Create a class called recursiveSum which will compute and print the sum of an integer on the screen

public class Pattern25
{
public static void main(String[] args)
{
int left = 1, right = 1;
for(int i = 1; i <=5; i++)
{
for(int k = 1; k <= left; k++)
{
System.out.print(k);
}
System.out.print(" ");
for(int k = right; k >= 1; k--)
{
System.out.print(k);
}
right++;
left++;
System.out.println();
}
}
}

import java.util.Scanner;

public class Pattern28
{
public static void main(String[] args)
{
System.out.println("Enter the number of rows in Pattern");
Scanner scn = new Scanner(System.in);
int row_num = scn.nextInt();
for(int i = 1; i <= row_num; i++)
{
if((i % 2) != 0)
{
for(int j = 1; j <= 5; j++)
{
System.out.print(i);
}
System.out.print(i+1);
}
else
{
System.out.print(i+1);
for(int j = 1; j <= 5; j++)
{
System.out.print(i);
}
}
System.out.println();
}
}
}

import java.util.Scanner;

public class Pattern29
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.println("Enter the number of rows of pattern you want : ");
int row_num = sc.nextInt();
int patt_num = 1;
int inc = 3;
int first_inc = 1;
int second_inc = 0;
for(int i = 1; i <= row_num; i++)
{
if(i == patt_num)
{
for(int j = 1; j <= first_inc; j++)
{
System.out.print(j);
}
patt_num = patt_num + inc;
inc++;
first_inc = first_inc + 2;
second_inc = second_inc + 2;
}
else
{
for(int j = 1; j <= second_inc; j++)
{
System.out.print(j);
}
}
System.out.println();
}
}
}

can u pls help me solve these 2 programs using only 2 for loops....

1) 3
2 3 4
1 2 3 4 5

AND

2) 1 2 3 4 5
2 3 4
3

public class Pattern32
{
public static void main(String[] args)
{
int start = 1,end = 3;
for(int i = 1; i <= 3; i++)
{
for(int j = start; j <= end; j++)
{
System.out.print(j);
}
start = start + 3;
end = end + 3;
System.out.println();
}
}
}

public class Pattern33
{
public static void main(String[] args)
{
int end = 5;
for(int i = 1; i <= 5; i++)
{
for(int j = 1; j <= end; j++)
{
System.out.print(j);
}
System.out.print(" ");
for(int j = end; j >= 1; j--)
{
System.out.print(j);
}
end--;
System.out.println();
}
}
}

What will be the programme for this pattern:
_____1
____21
___321
__4321
_54321

-----*
---* * *
-* * * * *
pls

select any three numbers between 0-9 and to find the probability pattern of that three numbers

for example:

if i selected as 123 then output will be as:

1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1

how to print given string in w format
p g m
r a
o r

Pls solve this pattern
2
4 6
8 10 12
14 16 18 20

can anyone help me for this pattern
12345
23456
34567
45678
56789